OK, if you take all the letters in Bill Gates III and then convert it in ASCII code (American standard code for information interchange) and then ADD up all the numbers…you will get 666, which is the number of the beast!!!
B = 66
I = 73
L = 76
L = 76
G = 71
A = 65
T = 84
E = 69
S = 83
I = 1
I = 1
I = 1= 666 !!!! THE NUMBER OF THE DEVIL
First off, you took an uncommon form of his name. I have never heard anybody refer to him as Bill Gates III before. It’s usually been just Bill Gates, though I’ve seen William Gates, William Gates III, and even his full name William Henry Gates III.
Secondly, you left out all spaces. His name is Bill Gates III, not Billgatesiii (which actually would be kinda cool. . .it sounds like a tribe of the Belgae or something like that). So you need to add 64 to your total sum there.
B = 66
I = 73
L = 76
L = 76
_ = 32
G = 71
A = 65
T = 84
E = 69
S = 83
_ = 32
I = 1
I = 1
I = 1
= 730 total
And you have two different values going for the letter “I”: 73 at first, and 1 later. If you’re going to have “secret messages” encoded in these things, then you need to have the key be consistent. So “I” can be equal to 73 in all cases, or else to 1. ASCII code seems to feel that it ought to be 73.
What does that give us?
B = 66
I = 73
L = 76
L = 76
_ = 32
G = 71
A = 65
T = 84
E = 69
S = 83
_ = 32
I = 73
I = 73
I = 73
= 946 total.
Or you could count those three I’s as representing the number one. But “1” in ASCII is not 1. It is 49.
B = 66
I = 73
L = 76
L = 76
_ = 32
G = 71
A = 65
T = 84
E = 69
S = 83
_ = 32
I (one) = 49
I (one) = 49
I (one) = 49
= 874 total
You also wrote it all in capital letters; using lower cased where normally they’re used would give you a totally different sum. As would using some of the other number codes that are used for ASCII, such as the one where B is 42, I is 49, and so on.
So really, you only get 666 if you set it all up artificially and inconsistently to do so.

